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3u^2-8u-11=0
a = 3; b = -8; c = -11;
Δ = b2-4ac
Δ = -82-4·3·(-11)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-14}{2*3}=\frac{-6}{6} =-1 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+14}{2*3}=\frac{22}{6} =3+2/3 $
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